4.9x^2-9.2x-16=0

Solution for 4.9x^2-9.2x-16=0 equation:

4.9x^2-9.2x-16=0

a = 4.9; b = -9.2; c = -16;
Δ = b2-4ac
Δ = -9.22-4·4.9·(-16)
Δ = 398.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.2)-\sqrt{398.24}}{2*4.9}=\frac{9.2-\sqrt{398.24}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.2)+\sqrt{398.24}}{2*4.9}=\frac{9.2+\sqrt{398.24}}{9.8}
$